document.write( "Question 92117: show the equation used for the solution.
\n" ); document.write( "The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
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Algebra.Com's Answer #66972 by anraymer(35)\"\" \"About 
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L = 2 + 2W
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "P = 34 in.
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\n" ); document.write( "34 = 2L + 2W
\n" ); document.write( "34 = 2(L + W)
\n" ); document.write( "17 = L + W
\n" ); document.write( "17 - W = L
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\n" ); document.write( "L = 2 + 2W
\n" ); document.write( "17 - W = 2 + 2W
\n" ); document.write( "17 = 2 + 3W
\n" ); document.write( "15 = 3W
\n" ); document.write( "W = 5 in.
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\n" ); document.write( "L = 2 + 2W
\n" ); document.write( "L = 2 + 2(5)
\n" ); document.write( "L = 2 + 10
\n" ); document.write( "L = 12 in.
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