document.write( "Question 92117: show the equation used for the solution.
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document.write( "The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #66972 by anraymer(35)![]() ![]() ![]() You can put this solution on YOUR website! L = 2 + 2W \n" ); document.write( "P = 2L + 2W \n" ); document.write( "P = 34 in. \n" ); document.write( " \n" ); document.write( "34 = 2L + 2W \n" ); document.write( "34 = 2(L + W) \n" ); document.write( "17 = L + W \n" ); document.write( "17 - W = L \n" ); document.write( " \n" ); document.write( "L = 2 + 2W \n" ); document.write( "17 - W = 2 + 2W \n" ); document.write( "17 = 2 + 3W \n" ); document.write( "15 = 3W \n" ); document.write( "W = 5 in. \n" ); document.write( " \n" ); document.write( "L = 2 + 2W \n" ); document.write( "L = 2 + 2(5) \n" ); document.write( "L = 2 + 10 \n" ); document.write( "L = 12 in. \n" ); document.write( " |