document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054438>Question 1054438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The time T necessary to make an enlargement of a photo of negative varies directly as the area A of the enlargement.  If 180 seconds are required to make a 5-by-7 enlargement, find the time required for 6-by-6 enlargement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669664 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 180 seconds=k*35 (the square inches in 5*7)<BR>\n" );
document.write( "k=180/35<BR>\n" );
document.write( "x seconds=k*36=(180/35)*36<BR>\n" );
document.write( "x=185.14 seconds. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );