document.write( "Question 1054401: A's age is six times B's,and fifteen years hence A will be three times as old as B. find their ages \n" ); document.write( "
Algebra.Com's Answer #669626 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let b be B's age. Then A is 6b. So: \n" ); document.write( "3(b+15)=6b+15 \n" ); document.write( "3b+30=6b \n" ); document.write( "3b=30 \n" ); document.write( "b=10 \n" ); document.write( "B is 10 years old; A is 60. ☺☺☺☺ \n" ); document.write( " |