document.write( "Question 1054394: Solve.\r
\n" ); document.write( "\n" ); document.write( "\"+log2%283-7x%29=log2%286x%5E2%29+\"\r
\n" ); document.write( "\n" ); document.write( "Can someone be generous enough to help me? Please & thanks!
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Algebra.Com's Answer #669616 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\"+log2%283-7x%29=log2%286x%5E2%29+\", both log2
\n" ); document.write( "6x^2 = 3-7x
\n" ); document.write( "6x^2 + 7x - 3 = 0
\n" ); document.write( "(3x-1)(2x +3) = 0
\n" ); document.write( "x = 1/3
\n" ); document.write( "0r
\n" ); document.write( "x = -3/2
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