document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054356>Question 1054356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 10% salt solution should be added to 20 gallons of a 60% salt solution to obtain a 50% salt solution?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669579 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.10x+0.60(20) = 0.50(x+20)<BR>\n" );
document.write( "0.10x+12 = 0.50x+10 substract 0.10x and 10 from both sides<BR>\n" );
document.write( "2 = 0.40x flip it<BR>\n" );
document.write( "0.40x = 2 divide both sides by 0.40<BR>\n" );
document.write( "x = 5 gallons of the 60% solution should be added to the 20 gallon to obtain a 50% solution<BR>\n" );
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