document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054328>Question 1054328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company manufactures both liquid crystal display (LCD) and cathode ray tube (CRT) color monitors. The cost of materials for a CRT monitor is $60, whereas the cost of materials for an LCD monitor is $120. The cost of labor to manufacture a CRT monitor is $90, whereas the cost of labor to manufacture an LCD monitor is $130. During a week when the company has budgeted $9720 for materials and $11580 for labor, how many LCD monitors does the company plan to manufacture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669566 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> set up a table as follows:\r<BR>\n" );
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document.write( "                  x                  y         \r\n" );
document.write( "                 CRT                LCD            total \r\n" );
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document.write( "material         60                 120             = 9720\r\n" );
document.write( "labor            90                 130             = 11580\r\n" );
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document.write( "x is equal to the number of CRT.<BR>\n" );
document.write( "y is equal to the number of LCD\r<BR>\n" );
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document.write( "total material is equal to 9720.<BR>\n" );
document.write( "total labor is equal to 11580.\r<BR>\n" );
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document.write( "you have two equations that need to be solved simultaneously.\r<BR>\n" );
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document.write( "they are:\r<BR>\n" );
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document.write( "60x + 120y = 9720<BR>\n" );
document.write( "90x + 130y = 11580\r<BR>\n" );
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document.write( "we'll solve by elimination.\r<BR>\n" );
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document.write( "multiply both sides of the first equation by 1.5 and leave the second equation as is to get:\r<BR>\n" );
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document.write( "90x + 180y = 14580<BR>\n" );
document.write( "90x + 130y = 11580\r<BR>\n" );
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document.write( "subtract the second equation from the first equation to get:\r<BR>\n" );
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document.write( "50y = 3000\r<BR>\n" );
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document.write( "solve for y to get y = 60\r<BR>\n" );
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document.write( "replace y in the first original equation with 60 and solve for x to get:<BR>\n" );
document.write( "60x + 120y = 9720 becomes 60x + 7200 = 9720.<BR>\n" );
document.write( "solve for x to get x = 42.\r<BR>\n" );
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document.write( "your solution is x = 42 and y = 60\r<BR>\n" );
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document.write( "this means that you will manufacture 42 CRT and 60 LCD.\r<BR>\n" );
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document.write( "your original equations of:\r<BR>\n" );
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document.write( "60x + 120y = 9720<BR>\n" );
document.write( "90x + 130y = 11580\r<BR>\n" );
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document.write( "become:\r<BR>\n" );
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document.write( "60 * 42 + 120 * 60 = 9720<BR>\n" );
document.write( "90 * 42 + 130 * 60 = 11580\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "9720 = 9720<BR>\n" );
document.write( "11580 = 11580\r<BR>\n" );
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document.write( "x represents the number of CRT which is equal to 42.<BR>\n" );
document.write( "y represents the number of LCD which is equal to 60.\r<BR>\n" );
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document.write( "solution looks good.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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