document.write( "Question 1054306: For what value of k does x^2 + kx + 1 = 0 have two different real roots? \r
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document.write( "This is what I have done so far:\r
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document.write( "D > 0\r
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document.write( "k^2 - 4(1)(1) > 0\r
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document.write( "k^2 > 4\r
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document.write( "sqrt(k) > + or - sqrt(4)\r
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document.write( "k > + or - 2\r
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document.write( "My answer sheet says k < -2 or k > 2, but I don't understand how to get to that answer. \n" );
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Algebra.Com's Answer #669513 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the discriminant, b^2-4ac=k^2-4>0 \n" ); document.write( "k^2>4 \n" ); document.write( "abs(k)>2 \n" ); document.write( "that means k>2 OR k<-2 \n" ); document.write( " |