document.write( "Question 92075This question is from textbook algebra and trigonometry
\n" ); document.write( ": can someone help me,i dont get this!!! Find the dimensions of a rectangle a with the greatest area whose perimeter is 30 feet. i dont get this!!! \n" ); document.write( "
Algebra.Com's Answer #66949 by scott8148(6628)\"\" \"About 
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the perimeter (2L+2W) is 30 ... 2(L+W)=30 ... L+W=15 ... L=15-W ... so the area is A=(L)(W) ... A=(15-W)(W) ... A=15W-W^2\r
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\n" ); document.write( "\n" ); document.write( "the maximum value for A occurs on the axis of symmetry of the graph\r
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\n" ); document.write( "\n" ); document.write( "the equation of the axis of symmetry for ax^2+bx+c is x=-b/2a\r
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\n" ); document.write( "\n" ); document.write( "in this case W=-15/2(-1) or W=7.5 ... since L+W=15, L=7.5\r
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\n" ); document.write( "\n" ); document.write( "the rectangle of perimeter 30 with the greatest area is a square with side 7.5
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