document.write( "Question 92075This question is from textbook algebra and trigonometry
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document.write( ": can someone help me,i dont get this!!! Find the dimensions of a rectangle a with the greatest area whose perimeter is 30 feet. i dont get this!!! \n" );
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Algebra.Com's Answer #66948 by mathispowerful(115)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First there are more than one way to do it, since this is algebra.com, I will use quadratic equation to solve it.\r \n" ); document.write( "\n" ); document.write( "Let x, y represent length and width of the rectangle.\r \n" ); document.write( "\n" ); document.write( " then we have x+y = 15\r \n" ); document.write( "\n" ); document.write( "we need to find maximum area, A. A = length times width = xy\r \n" ); document.write( "\n" ); document.write( "from x+y = 15, y = 15 - x\r \n" ); document.write( "\n" ); document.write( "in A=xy, substitute y by 15 - x\r \n" ); document.write( "\n" ); document.write( "A = x(15 - x)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is a quadratic equation, the maximum value is at \n" ); document.write( "\n" ); document.write( "so x = 7.5, then y = 15 -x = 7.5\r \n" ); document.write( "\n" ); document.write( "so it will be a square with length of 7.5 ft. \n" ); document.write( " \n" ); document.write( " |