document.write( "Question 91882: Solve\r
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document.write( "2z/5 = z-1/3 \n" );
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Algebra.Com's Answer #66947 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 15 to get rid of those denominators, resulting in: \n" ); document.write( "3(2z) = 15z - 5(1) \n" ); document.write( ": \n" ); document.write( "6z = 15z - 5 \n" ); document.write( ": \n" ); document.write( "+5 = 15z - 6z \n" ); document.write( ": \n" ); document.write( "5 = 9z \n" ); document.write( ": \n" ); document.write( "z = 5/9 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |