document.write( "Question 91882: Solve\r
\n" ); document.write( "\n" ); document.write( "2z/5 = z-1/3
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Algebra.Com's Answer #66947 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve
\n" ); document.write( "\"2z%2F5\" = \"z+-+1%2F3\"
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\n" ); document.write( "Multiply equation by 15 to get rid of those denominators, resulting in:
\n" ); document.write( "3(2z) = 15z - 5(1)
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\n" ); document.write( "6z = 15z - 5
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\n" ); document.write( "+5 = 15z - 6z
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\n" ); document.write( "5 = 9z
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\n" ); document.write( "z = 5/9
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "\"2%285%2F9%29%2F5\" = \"%285%2F9%29+-+1%2F3\"
\n" ); document.write( "\"10%2F9%2F5\" = \"%285%2F9%29+-+1%2F3\"
\n" ); document.write( "\"2%2F9\" = \"5%2F9+-+3%2F9\"
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