document.write( "Question 1054247: Savanah invested $13,000 in two different types of bonds. One bond earned 4% annual interest and the other earned 6% annual interest. After the first year, she earned $670 in interest. How much money did she invest in each bond? \n" ); document.write( "
Algebra.Com's Answer #669466 by addingup(3677)\"\" \"About 
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Total invested: 13,000
\n" ); document.write( "At 4%: x
\n" ); document.write( "At 6%: 13,000-x
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\n" ); document.write( "0.04x+0.06(13000-x) = 670
\n" ); document.write( "0.04x+780-0.06x = 670
\n" ); document.write( "-0.02x = -110 Divide both sides by -0.02 and remember -/- = +
\n" ); document.write( "x = 5,500 this is how much is invested at 4%
\n" ); document.write( "and 13,000-5,500 = 7,500 is invested at 6%
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\n" ); document.write( "Check:
\n" ); document.write( "5,500(0.04) = 220
\n" ); document.write( "7,500(0.06) = 450
\n" ); document.write( "Total .. .. .670 Correct
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\n" ); document.write( "John
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