document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92100>Question 92100</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I am not ggod at word problems and I am having trouble on this one<BR>\n" );
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document.write( "The eqaution H=-16t^2+112t gives the height of an arrow, shot upward from the ground with initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. find the time it takes for the arrow to reach a height of 180ft.\r<BR>\n" );
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document.write( "Thanks a million </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66940 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation H=-16t^2+112t gives the height of an arrow, shot upward from the ground with initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. find the time it takes for the arrow to reach a height of 180ft. <BR>\n" );
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document.write( "Let H=180 and solve for t:<BR>\n" );
document.write( "-16t^2+112t-180=0<BR>\n" );
document.write( "t^2-7t+12 = 0<BR>\n" );
document.write( "(t-3)(t-4)=0<BR>\n" );
document.write( "t =3 seconds or t = 4 seconds<BR>\n" );
document.write( "The 3 seconds is on the way up; the 4 seconds is on the way down.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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