document.write( "Question 13332: Anne has some number of cookies which she wants to distribute to kids in the room. If she gives each kid 9 cookies, 1 cookies will be left in her hand \"9n+%2B+1+=+C\". If she tries to give each kid 10 cookies, she will need more 13 cookies than she has now \"10n+=+c+%2B+13\". How many kids are there in the room? \n" ); document.write( "
Algebra.Com's Answer #6694 by akmb1215(68)\"\" \"About 
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First of all, you need to set up equations to fit the problem. I have added these to your question. I have used C as the number of cookies, and n as the number of students in the room. Now that you know the equations, you can substitute 9n+1 for C in the second equation to get \"10n+=+%289n+%2B+1%29+%2B+13\". To solve, first add like terms to get \"10n+=+9n+%2B+14\". Then, move 9n over to get \"1n+=+14\". There are 14 kids in the class. \n" ); document.write( "
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