document.write( "Question 1054121: the length of a rectangle is one more than six times the width. the area is two feet squared. find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #669380 by Fombitz(32388) $\"\"$ $\"About$

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$\"L=1%2B6W\"$
\n" ); document.write( " $\"A=L%2AW=2\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"%281%2B6W%29W=2\"$
\n" ); document.write( " $\"W%2B6W%5E2=2\"$
\n" ); document.write( " $\"6W%5E2%2BW-2=0\"$
\n" ); document.write( " $\"%282W-1%29%283W%2B2%29=0\"$
\n" ); document.write( "Only positive W values are allowed.
\n" ); document.write( " $\"2W-1=0\"$
\n" ); document.write( " $\"2W=1\"$
\n" ); document.write( " $\"W=1%2F2\"$ $\"ft\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"L=1%2B6%281%2F2%29\"$
\n" ); document.write( " $\"L=1%2B3\"$
\n" ); document.write( " $\"L=4\"$ $\"ft\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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