document.write( "Question 1054159: At 9:00 a.m., Your friends begin hiking at 2mi/h. You begin from the same place at 9:25 a.m. You hike at 3mi/h.\r
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document.write( "a. How long will you have hiked when you catch up with your friends?
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document.write( "b. At what time will you catch up with your friends? \n" );
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Algebra.Com's Answer #669372 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! 9:25 minus 9:00 = 25 min \n" ); document.write( "25 min = \n" ); document.write( "------------------------ \n" ); document.write( "What is your friend's head start in miles? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "Start a stopwatch when you start hiking and \n" ); document.write( "stop it when you catch up with friends \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "until you catch up with friends \n" ); document.write( "---------------------------------------- \n" ); document.write( "Your equation: \n" ); document.write( "(1) \n" ); document.write( "Friend's equation: \n" ); document.write( "(2) \n" ); document.write( "----------------------- \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "---------------------- \n" ); document.write( "(a) \n" ); document.write( "You hike 2.5 mi until you catch up with friends \n" ); document.write( "(b) \n" ); document.write( " \n" ); document.write( "9:25 + 50 min = 10:15 \n" ); document.write( "You catch up with friends at 10:15 \n" ); document.write( "------------------------------------ \n" ); document.write( "check: \n" ); document.write( "Your friends should cover \n" ); document.write( "= 75 min which is 1.25 hrs \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |