document.write( "Question 1054159: At 9:00 a.m., Your friends begin hiking at 2mi/h. You begin from the same place at 9:25 a.m. You hike at 3mi/h.\r
\n" ); document.write( "\n" ); document.write( "a. How long will you have hiked when you catch up with your friends?
\n" ); document.write( "b. At what time will you catch up with your friends?
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Algebra.Com's Answer #669372 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
9:25 minus 9:00 = 25 min
\n" ); document.write( "25 min = \"++25%2F60+\" hrs
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\n" ); document.write( "What is your friend's head start in miles?
\n" ); document.write( "\"+d%5B1%5D+=+2%2A%2825%2F60%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+5%2F6++\" mi
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\n" ); document.write( "Start a stopwatch when you start hiking and
\n" ); document.write( "stop it when you catch up with friends
\n" ); document.write( "Let \"+t+\" = time on stopwatch in hrs
\n" ); document.write( "Let \"+d+\" = distance in miles you travel
\n" ); document.write( "until you catch up with friends
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\n" ); document.write( "Your equation:
\n" ); document.write( "(1) \"+d+=+3t+\"
\n" ); document.write( "Friend's equation:
\n" ); document.write( "(2) \"+d+-+5%2F6+=+2t+\"
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\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+3t+-+5%2F6+=+2t+\"
\n" ); document.write( "(2) \"+t+=+5%2F6+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+3%2A%285%2F6%29+\"
\n" ); document.write( "(1) \"+d+=+5%2F2+\"
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\n" ); document.write( "(a)
\n" ); document.write( "You hike 2.5 mi until you catch up with friends
\n" ); document.write( "(b)
\n" ); document.write( "\"+5%2F6+=+50%2F60+\" hrs
\n" ); document.write( "9:25 + 50 min = 10:15
\n" ); document.write( "You catch up with friends at 10:15
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\n" ); document.write( "check:
\n" ); document.write( "Your friends should cover \"+2.5+\" mi in 25 min plus 50 min
\n" ); document.write( "= 75 min which is 1.25 hrs
\n" ); document.write( "\"+d+=+2%2A1.25+\"
\n" ); document.write( "\"+d+=+2.5+\" mi
\n" ); document.write( "OK\r
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