document.write( "Question 1054176: Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time. \r
\n" ); document.write( "\n" ); document.write( "Find the rate of the canoest in calm water and the rate of the current.
\n" ); document.write( "

Algebra.Com's Answer #669361 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time. \r
\n" ); document.write( "\n" ); document.write( "Find the rate of the canoeist in calm water and the rate of the current.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Your equations are\r\n" );
document.write( "\r\n" );
document.write( "(1)  \"18%2F3\" = u + v,   (\"Rowing with the current, a canoeist paddled 18 mi in 3 h\")\r\n" );
document.write( "\r\n" );
document.write( "(2)  \"6%2F3\" = u - v.    (\"Against the current, the canoeist could paddle only 6 mi in the same amount of time.\")\r\n" );
document.write( "\r\n" );
document.write( "Here u is the rate of the canoeist in calm water and v is the rate of the current.\r\n" );
document.write( "\r\n" );
document.write( "Simplify equations (1) and (2). You will get\r\n" );
document.write( "\r\n" );
document.write( "u + v = 6,   (3)\r\n" );
document.write( "u - v = 3.   (4)\r\n" );
document.write( "\r\n" );
document.write( "Add equations (3) and (4). You will get\r\n" );
document.write( "\r\n" );
document.write( "2u = 6 + 3 = 9  --->  u = \"9%2F2\" = 4.5.\r\n" );
document.write( "\r\n" );
document.write( "Thus you just found the rate of the canoeist in calm water. It is 4.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Now find v from (3):\r\n" );
document.write( "\r\n" );
document.write( "v = 6 - u = 6 - 4.5 = 1.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Answer.  The rate of the canoeist in calm water is 4.5 mph.\r\n" );
document.write( "         The rate of the current is 1.5 mph.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "It is a typical Upstream and Downstream Travel and Distance problem.\r
\n" ); document.write( "\n" ); document.write( "You can find similar fully solved similar problems on upstream and downstream trips with detailed solutions in the lessons \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems \r
\n" ); document.write( "\n" ); document.write( "    - More problems on upstream and downstream round trips \r
\n" ); document.write( "\n" ); document.write( "    - Selected problems from the archive on the boat floating Upstream and Downstream \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Read them attentively and learn how to solve this type of problems once and for all.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook under the section \"Word problems\", the topic \"Travel and Distance problems\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );