document.write( "Question 1054145: Mark made a business trip of 339.5 miles. He averaged 56 mph for the first part of the trip and 57 mph for the second part. If the trip took 6 hours, how long did he travel at each rate? \n" ); document.write( "
Algebra.Com's Answer #669354 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = distance in miles traveled
\n" ); document.write( "on the 1st part of the trip
\n" ); document.write( "\"+339.5+-+d+\" = distance in miles traveled
\n" ); document.write( "on the 2nd part of the trip
\n" ); document.write( "Let \"+t+\" = time in hrs for 1st part of the trip
\n" ); document.write( "\"+6+-+t+\" = time in hrs for the 2nd part of the trip
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "Equation for the 1st part:
\n" ); document.write( "(1) \"+d+=+56t+\"
\n" ); document.write( "Equation for the 2nd part:
\n" ); document.write( "(2) \"+339.5+-+d+=+57%2A%28+6+-+t+%29+\"
\n" ); document.write( "--------------------------------
\n" ); document.write( "(2) \"+339.5+-+d+=+342+-+57t+\"
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+339.5+-+56t+=+342+-+57t+\"
\n" ); document.write( "(2) \"+57t+-+56t+=+342+-+339.5+\"
\n" ); document.write( "(2) \"+t+=+2.5+\"
\n" ); document.write( "and
\n" ); document.write( "\"+6+-+t+=+6+-+2.5+\"
\n" ); document.write( "\"+6+-+t+=+3.5+\"
\n" ); document.write( "--------------------
\n" ); document.write( "He traveled for 2.5 hrs at 56 mi/hr
\n" ); document.write( "He traveled for 3.5 hrs at 57 mi/hr
\n" ); document.write( "----------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+56t+\"
\n" ); document.write( "(1) \"+d+=+56%2A2.5+\"
\n" ); document.write( "(1) \"+d+=+140+\" mi
\n" ); document.write( "and
\n" ); document.write( "(2) \"+339.5+-+d+=+57%2A%28+6+-+2.5+%29+\"
\n" ); document.write( "(2) \"+339.5+-+d+=+342+-+142.5+\"
\n" ); document.write( "(2) \"+d+=+339.5+-+342+%2B+142.5+\"
\n" ); document.write( "(2) \"+d+=+482+-+342+\"
\n" ); document.write( "(2) \"+d+=+140+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
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