document.write( "Question 1054156: Two airplanes depart from an airport traveling in opposite directions. The second airplane is 200 miles per hour faster than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes? \n" ); document.write( "

Algebra.Com's Answer #669353 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Two airplanes depart from an airport traveling in opposite directions. The second airplane is 200 miles per hour faster
\n" ); document.write( "than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes?
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document.write( "2*(x + (x+200)) = 1100.    (It is the \"distance\" equation D = R*T)\r\n" );
document.write( "                           (Here \"x\" is the speed of the slowest plane)\r\n" );
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document.write( "Simplfy and solve for x:\r\n" );
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document.write( "2x + 2x + 400 = 1100  --->\r\n" );
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document.write( "4x = 1100-400,\r\n" );
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document.write( "4x = 700   --->  x =  = 175 mph.\r\n" );
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document.write( "Answer.  The speed of the slowest plane is 175 mph.\r\n" );
document.write( "         The speed ot the other plane is 175+200 = 375 mph.\r\n" );
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document.write( "Check.  2*(175+375) = 2*550 = 1100.   Correct!\r\n" );
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