document.write( "Question 1054153: Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at a rate of 48 mi/h. At what time will john catch up with martina.
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Algebra.Com's Answer #669351 by ikleyn(52810)\"\" \"About 
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\n" ); document.write( "Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at a rate of 48 mi/h. At what time will john catch up with martina.
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\n" ); document.write( "\n" ); document.write( "Answer. At 1:00 pm.\r
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document.write( "John will catch Martina in 2 hours after his start:\r\n" );
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document.write( "time = \"%282%2A24%29%2F%2848-24%29\" = \"48%2F24\" = 2 hours.\r\n" );
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document.write( "Here 2*24 is the distance between them at 11:00 am when John start his move.\r\n" );
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document.write( "The difference (48-24) in the denominator is their relative speed.\r\n" );
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