document.write( "Question 1053927: In the figure, a sealed conical vessel of height 10 cm contains some water to a mark M. When it is inverted, the water surface is still at the mark M. Find the ratio of the volume of water to the capacity of the vessel. Then find the height of the mark M above the vertex of the vessel to 3dp.\r
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Algebra.Com's Answer #669349 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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In the figure, a sealed conical vessel of height 10 cm contains some water to a mark M.
\n" ); document.write( "When it is inverted, the water surface is still at the mark M.
\n" ); document.write( "Find the ratio of the volume of water to the capacity of the vessel.
\n" ); document.write( "the volume above the line equals the volume below the line
\n" ); document.write( "1:2 = water to capacity ratio
\n" ); document.write( ":
\n" ); document.write( "Then find the height of the mark M above the vertex of the vessel to 3dp.
\n" ); document.write( "If this were a cylinder, m would be half way or 5 inches
\n" ); document.write( "Because a cone shape and the 1/3 in vol formula:
\n" ); document.write( " $\"2%2F3\"$ *10 = 6.667 inches is the height of M from the vertex \n" ); document.write( "

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