document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054127>Question 1054127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular plot of land has a length x and a width y, and has a perimeter of 124 m and an area of 945 m2. Find the value of x and y.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669335 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+2y=124<BR>\n" );
document.write( "x+y=62<BR>\n" );
document.write( "xy=945<BR>\n" );
document.write( "x=-y+62<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "(-y+62)y=945<BR>\n" );
document.write( "-y^2+62y=945<BR>\n" );
document.write( "0=y^2-62y+945<BR>\n" );
document.write( "y=(1/2)+/-(62+/- sqrt (62^2-4(945)); sqrt term is sqrt (64)<BR>\n" );
document.write( "y=(1/2)+/- (62+/-8)<BR>\n" );
document.write( "y=35, 27 units m<BR>\n" );
document.write( "That gives a half perimeter of 62 m and a full perimeter of 124 m<BR>\n" );
document.write( "area is 945 m^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );