document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054081>Question 1054081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tanya has a triangular garden bed in her back yard. The measure of the second angle is 60 degrees more than the measure of the first angle. The measure of the third angle is 20 degrees less than three times the measure of the first angle. Find the measures of the three angles. Start your work by defining the unknown quantities in terms of a variable. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669308 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+60 second angle: 1st angle + 60<BR>\n" );
document.write( "3x-20 3rd angle: 20 less than 3 times first angle<BR>\n" );
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document.write( "Theorem: The sum of the three angles in a triangle is always 180º<BR>\n" );
document.write( "Thus:<BR>\n" );
document.write( "x+x+60+3x-20 = 180<BR>\n" );
document.write( "5x+40 = 180<BR>\n" );
document.write( "5x = 140<BR>\n" );
document.write( "x = 28<BR>\n" );
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document.write( "Angle 1: 28<BR>\n" );
document.write( "Angle 2: 28+60 = 88<BR>\n" );
document.write( "Angle 3: 3(28)-20 = 64<BR>\n" );
document.write( "Triangle: 28+88+64 = 180 Correct<BR>\n" );
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document.write( "John </SPAN>\n" );
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