document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054097>Question 1054097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use this new algebraic method to find equations for lines with the following properties:<BR>\n" );
document.write( "A. A slope of -3, passing through the point (15,-50)<BR>\n" );
document.write( "B. A slope of 0.5 with an x-intercept of (28,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669302 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Presumably, one wants the point-slope formula<BR>\n" );
document.write( "y-y1=m(x-x1)<BR>\n" );
document.write( "For the first<BR>\n" );
document.write( "y-(-50)=-3(x-15)<BR>\n" );
document.write( "y+50=-3x+45<BR>\n" );
document.write( "y=-3x-5; -50=-45-5, check<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "y=0.5(x-28)<BR>\n" );
document.write( "y=(1/2)x-14; 28(1/2)-14=0, check </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );