document.write( "Question 92090: I am having trouble solving this problem. Can somebody please help me.
\n" ); document.write( "L has y-intercept (0,2) and is perpendicular to the line with equation
\n" ); document.write( "2x-3y=6.
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Algebra.Com's Answer #66926 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First convert 2x-3y=6 into slope intercept form\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"2x-3y=6\" Start with the given equation


\"2x-3y-2x=6-2x\" Subtract 2x from both sides


\"-3y=-2x%2B6\" Simplify


\"%28-3y%29%2F%28-3%29=%28-2x%2B6%29%2F%28-3%29\" Divide both sides by -3 to isolate y


\"y+=+%28-2x%29%2F%28-3%29%2B%286%29%2F%28-3%29\" Break up the fraction on the right hand side


\"y+=+%282%2F3%29x-2\" Reduce and simplify


The original equation \"2x-3y=6\" (standard form) is equivalent to \"y+=+%282%2F3%29x-2\" (slope-intercept form)


The equation \"y+=+%282%2F3%29x-2\" is in the form \"y=mx%2Bb\" where \"m=2%2F3\" is the slope and \"b=-2\" is the y intercept.



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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"2%2F3\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%282%2F3%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%283%2F2%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=-3%2F2\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"-3%2F2\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"-3%2F2\" (its the negative reciprocal of \"2%2F3\" from the line \"y=%282%2F3%29%2Ax-2\").\n" ); document.write( "Also since the unknown line goes through (0,2), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-2=%28-3%2F2%29%2A%28x-0%29\" Plug in \"m=-3%2F2\", \"x%5B1%5D=0\", and \"y%5B1%5D=2\"
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\n" ); document.write( " \"y-2=%28-3%2F2%29%2Ax%2B%283%2F2%29%280%29\" Distribute \"-3%2F2\"
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\n" ); document.write( " \"y-2=%28-3%2F2%29%2Ax-0%2F2\" Multiply
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\n" ); document.write( " \"y=%28-3%2F2%29%2Ax-0%2F2%2B2\"Add \"2\" to both sides to isolate y
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\n" ); document.write( " \"y=%28-3%2F2%29%2Ax-0%2F2%2B4%2F2\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-3%2F2%29%2Ax%2B4%2F2\" Combine the fractions
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\n" ); document.write( " \"y=%28-3%2F2%29%2Ax%2B2\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%282%2F3%29%2Ax-2\" and goes through (\"0\",\"2\") is \"y=%28-3%2F2%29%2Ax%2B2\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%282%2F3%29%2Ax-2\" and \"y=%28-3%2F2%29%2Ax%2B2\"
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\n" ); document.write( " graph of the given equation \"y=%282%2F3%29%2Ax-2\" (red) and graph of the line \"y=%28-3%2F2%29%2Ax%2B2\"(green) that is perpendicular to the given graph and goes through (\"0\",\"2\")
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