document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053967>Question 1053967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The value of a car decreases at a constant rate. After 1 year the value of the car is $20,000. After 2 more years it is $14,000. Write an equation in slope-intercept that represents the value y (in dollars) of the car after x years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669206 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The value of a car decreases at a constant rate. After 1 year the value of the car is $20,000. After 2 more years it is $14,000. Write an equation in slope-intercept that represents the value y (in dollars) of the car after x years. <BR>\n" );
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document.write( "after 1 yr:: 20000<BR>\n" );
document.write( "after 2 yr:: 14000 = 20000-6000<BR>\n" );
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document.write( "original::20000+6000 = 26000<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "V(x) = 26000 - 6000x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H<BR>\n" );
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document.write( " </SPAN>\n" );
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