document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053928>Question 1053928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The volume of a sphere is 904.78 cu. m. Find the volume of the spherical segment of height 4 m. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669194 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume(Vs) of a sphere = (4/3) * pi * r^3, where r is the radius and pi is (22/7)<BR>\n" );
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document.write( "I assume that the problem's spherical segment has one base<BR>\n" );
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document.write( "V(ss) = (1/3) * pi * h^2 * (3R - h), where h is the height, R is the radius<BR>\n" );
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document.write( "904.78(Vs) = (4/3) * (22/7) * r^3<BR>\n" );
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document.write( "r^3 = 904.78 * 21 / 88<BR>\n" );
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document.write( "r = 5.9992 m<BR>\n" );
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document.write( "V(ss) = (1/3) * (22/7) * 4^2 * (3*5.9992-4) = 234.6264 approx 234.63<BR>\n" );
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document.write( "The volume of spherical segment is 234.63 cu m<BR>\n" );
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