document.write( "Question 1053922: The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation $1200. The daily revenue totals for the next 30 days will be monitored. What is the probability that the mean daily revenue for the next 30 days will exceed $7500?\r
\n" ); document.write( "\n" ); document.write( "How can I solve this with a calculator?
\n" ); document.write( "

Algebra.Com's Answer #669146 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
mean $7200 and standard deviation $1200.
\n" ); document.write( "n = 30, x̄ = mean daily revenue for the next 30 days
\n" ); document.write( "Need to Know: \"z+=blue+%28x-bar+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29\"
\n" ); document.write( "P(x̄ >7500) = 1- P(x̄ <= 7500) = 1- P(z <= \"%287500+-7200%29%2F+%281200%2Fsqrt%2830%29%29\")
\n" ); document.write( "Use Calculator to find value of z
\n" ); document.write( "then use Calculator to find P( z <= that value) = normalcdf(-100, z-value)
\n" ); document.write( "-100 a place value
\n" ); document.write( "
\n" ); document.write( "
\n" );