document.write( "Question 1053830: A, B & C can do a piece of work in 30,20 & 10 days respectively. A is assisted by B on one day & by C on the next day alternatively. How long would the work take to finish ? \n" ); document.write( "
Algebra.Com's Answer #669139 by ankor@dixie-net.com(22740)\"\" \"About 
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A, B & C can do a piece of work in 30,20 & 10 days respectively.
\n" ); document.write( " A is assisted by B on one day & by C on the next day alternatively.
\n" ); document.write( " How long would the work take to finish ?
\n" ); document.write( ":
\n" ); document.write( "let t = A's time to do the job with all working as described above
\n" ); document.write( "B & C worked half the time,therefore
\n" ); document.write( " .5t = time worked by B & C
\n" ); document.write( "let the completed job = 1
\n" ); document.write( "Each will do a fraction of the job, the 3 fractions add up to 1
\n" ); document.write( ":
\n" ); document.write( "\"t%2F30\" + \"%28.5t%29%2F20\" + \"%28.5t%29%2F10\" = 1
\n" ); document.write( "multiply equation by 300 to cancel the denominators
\n" ); document.write( "10t + 15(.5t) + 30(.5t) = 300
\n" ); document.write( "10t + 7.5t + 15t = 300
\n" ); document.write( "32.5t = 300
\n" ); document.write( "t = 90.231 days to complete job
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