document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053842>Question 1053842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (c) Use the gradient-y-intercept method to draw the graph of 5x + 2y + 3 = 0 and read the following from your graph: y when x = -1½ and x when<BR>\n" );
document.write( " y = ½. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669030 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x + 2y + 3 = 0<BR>\n" );
document.write( "y = (-5/2)x - 3/2<BR>\n" );
document.write( "P(1,-4) and P(0,-3/2) on this line:  Plot and connect<BR>\n" );
document.write( "(-3/2 ,2) and (-4/5, 1/5) are the points in question<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C+++-6%2C+6%2C+-6%2C+6%2C+grid%281%2F2%29%2C+%0D%0Acircle%281%2C+-4%2C0.3%29%2C%0D%0Acircle%280%2C+-3%2F2%2C+0.3%29%2C%0D%0Acircle%28-3%2F2%2C2%2C+0.3%29%2C%0D%0Acircle%28-.8%2C+1%2F2%2C0.3%29%2C%0D%0Agraph%28+300%2C+300%2C+-6%2C+6%2C+-6%2C+6%2C0%2C%28-5%2F2%29x+-+3%2F2+%29+%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );