document.write( "Question 1053825: Susan invests 2 times as much money at 8% as she does at 6%. If her total imterest after 1 year is $1,100. How much does she have invested at each rate? \r
\n" ); document.write( "\n" ); document.write( "I made an equation 2x+ y =1100 and 0.08x + 0.06y= $1100 but when i solve i get a negative number so i mnow my formulas are nit correct \n" ); document.write( "

Algebra.Com's Answer #669012 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Susan invests 2 times as much money at 8% as she does at 6%. If her total imterest after 1 year is $1,100. How much does she have invested at each rate? \r
\n" ); document.write( "\n" ); document.write( "I made an equation 2x+ y =1100 and 0.08x + 0.06y= $1100 but when i solve i get a negative number so i mnow my formulas are nit correct
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The correct approach is:
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document.write( "Let the amount invested at 6% be S
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document.write( "Then amount invested at 8% = 2S
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document.write( "Do you understand this?
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document.write( "Interest earned from 6% investment: .06S
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document.write( "Interest earned from 8% investment: .08(2S), or .16S
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document.write( "We then get the following TOTAL INTEREST AMOUNT equation: .06S + .16S = 1,100  
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document.write( "Solve this for S, the amount invested at 6%
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document.write( "Double or multiply value of S by 2 to get amount invested at 8%.
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document.write( "It's that easy....nothing complex! \n" );
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