document.write( "Question 1053800: Carl is 7 years older than Anne. Fifteen years from now Carl will be 33 years less than twice Anne's age at that time. How old is Carl now?\r
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Algebra.Com's Answer #669002 by addingup(3677)![]() ![]() You can put this solution on YOUR website! C = A+7 We'll use this value for C next \n" ); document.write( "and \n" ); document.write( "C+15 = 2(A+15)-33 Substitute for C on the left: \n" ); document.write( "A+7+15 = 2A+30-33 \n" ); document.write( "A+22 = 2A-3 Subtract A on both sides and add 3 on both sides: \n" ); document.write( "A-A+22+3 = 2A-A-3+3 Simplify: \n" ); document.write( "25 = A \n" ); document.write( "or, more elegantly: \n" ); document.write( "A = 25 Anne is 25 and so Carl is 25+7 = 32 \n" ); document.write( "------------------------------------------- \n" ); document.write( "In 15 years: \n" ); document.write( "Carl: 32+15 = 47 \n" ); document.write( "Anne:25+15 = 40 \n" ); document.write( "At that time, 15 years from now, Carl will be 2A-33. Let's see: \n" ); document.write( "47 = 2(40)-33 \n" ); document.write( "47 = 80-33 Correct \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " |