document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053767>Question 1053767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A supplement of an angle is 4 times the complement of the angle. find the measure of the angle. Then find the measure of its complement and supplement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668979 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A supplement of an angle is 4 times the complement of the angle. find the measure of the angle. Then find the measure of its complement and supplement <BR>\n" );
document.write( "------<BR>\n" );
document.write( "angle:: x<BR>\n" );
document.write( "supplement:: 180-x<BR>\n" );
document.write( "complement:: 90-x<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "180-x = 4(90-x)<BR>\n" );
document.write( "180-x = 360-4x<BR>\n" );
document.write( "3x = 180<BR>\n" );
document.write( "x = 60 degrees<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Ans: complement = 90-x = 30 degrees<BR>\n" );
document.write( "Ans: supplement = 180-x = 120 degrees<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );