document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91987>Question 91987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Last and final problem I am having troubles with is the following:<BR>\n" );
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document.write( "Find the solution set of :\r<BR>\n" );
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document.write( "1/k-1 + 1/k+2 = 3/k^2+k-2\r<BR>\n" );
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document.write( "Translation:<BR>\n" );
document.write( "Looks like 3 different terms to me:<BR>\n" );
document.write( "1 divided by k-1 + 1 divided by k+2 = 3 divided by k squared plus k-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66897 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the denominator on the right side is the common denominator for the two fractions on the left side\r<BR>\n" );
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document.write( "so (k+2)+(k-1)=3 ... 2k+1=3 ... 2k=2 ... k=1\r<BR>\n" );
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document.write( "BUT ... if k=1 then two of the denominators become 0, resulting in undefined quantities\r<BR>\n" );
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document.write( "this means that there is NO SOLUTION ... the solution set is the null set </SPAN>\n" );
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