document.write( "Question 1053751: What are the factors of a polynomial with the following zeroes: $\"+-1+\"$ , $\"+2%2F3+\"$ , $\"+2+\"$ \r
\n" ); document.write( "\n" ); document.write( "A.) (x-1)(x+⅔)(x-2)
\n" ); document.write( "B.) (x-1)(3x-2)(x-2)
\n" ); document.write( "C.) (x+1)(x-⅔)(x+2)
\n" ); document.write( "D.) (x+1)(3x-2)(x-2)\r
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Algebra.Com's Answer #668958 by Boreal(15235) $\"\"$ $\"About$

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The values are the result of setting the factors equal to 0. They are opposite to the values given\r
\n" ); document.write( "\n" ); document.write( "so if (x+1)=0, a zero is -1.
\n" ); document.write( "x-(2/3)=0, or x=2/3 or 3x+2=0.
\n" ); document.write( "(x-2)=0
\n" ); document.write( "D is the answer. We don't use fractions in factorization, so while (x-(2/3)) is not mathematically wrong, (3x-2) is the factor.\r
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