document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053728>Question 1053728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 4m less than the hypotenuse. The other leg is 2m less than the hypotenuse. Find the length of the hypotenuse </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668932 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hypotenuse is x<BR>\n" );
document.write( "one leg ix x-4<BR>\n" );
document.write( "the other is x-2<BR>\n" );
document.write( "The square of each leg added equals the square of the hypotenuse<BR>\n" );
document.write( "(x-4)^2+(x-2)^2=x^2=x^2-8x+16+x^2-4x+4<BR>\n" );
document.write( "x^2=2x^2-12x+20<BR>\n" );
document.write( "0=x^2-12x+20<BR>\n" );
document.write( "(x-10)(x+2)=0<BR>\n" );
document.write( "x=10, and -2, whic<BR>\n" );
document.write( "h is ignored<BR>\n" );
document.write( "The legs are 6 and 8 meters, and<BR>\n" );
document.write( "10 meters is the hypotenuse length. </SPAN>\n" );
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