document.write( "Question 92038: Solve by addition method. Indicate whether independent, inconsistent or dependent.\r
\n" ); document.write( "\n" ); document.write( "-3x + y =3
\n" ); document.write( "2x - 3y = 5
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Algebra.Com's Answer #66890 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"-3%2Ax%2B1%2Ay=3\"
\n" ); document.write( " \"2%2Ax-3%2Ay=5\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -3 and 2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of -3 and 2 is -6, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by 3 like this:
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\n" ); document.write( " \"2%2A%28-3%2Ax%2B1%2Ay%29=%283%29%2A2\" Multiply the top equation (both sides) by 2
\n" ); document.write( " \"3%2A%282%2Ax-3%2Ay%29=%285%29%2A3\" Multiply the bottom equation (both sides) by 3
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-6%2Ax%2B2%2Ay=6\"
\n" ); document.write( " \"6%2Ax-9%2Ay=15\"
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\n" ); document.write( " Notice how -6 and 6 add to zero (ie \"-6%2B6=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%28-6%2Ax%2B6%2Ax%29%2B%282%2Ay-9%2Ay%29=6%2B15\"
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\n" ); document.write( " \"%28-6%2B6%29%2Ax%2B%282-9%29y=6%2B15\"
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\n" ); document.write( " \"cross%28-6%2B6%29%2Ax%2B%282-9%29%2Ay=6%2B15\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-7%2Ay=21\"
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\n" ); document.write( " \"y=21%2F-7\" Divide both sides by \"-7\" to solve for y
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\n" ); document.write( " \"y=-3\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"-3%2Ax%2B1%2Ay=3\" to solve for x
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\n" ); document.write( " \"-3%2Ax%2B1%28-3%29=3\" Plug in \"y=-3\"
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\n" ); document.write( " \"-3%2Ax-3=3\" Multiply
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\n" ); document.write( " \"-3%2Ax=3%2B3\" Subtract \"-3\" from both sides
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\n" ); document.write( " \"-3%2Ax=6\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-3%29%28-3%29%29%2Ax=%286%29%281%2F-3%29\" Multiply both sides by \"1%2F-3\". This will cancel out \"-3\" on the left side.
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\n" ); document.write( " \"x=-2\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-2\", \"y=-3\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-2\", \"-3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"-3%2Ax%2B1%2Ay=3\"
\n" ); document.write( " \"2%2Ax-3%2Ay=5\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"-3%2Ax%2B1%2Ay=3\" (red) \"2%2Ax-3%2Ay=5\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-2\",\"-3\"). This verifies our answer.
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