document.write( "Question 1053659: A container holds 5 gallon of a gas oil mixture in a 50:1 ratio (gas to oil). How many fl oz of oil should be added to change the mixture into a 40:1 mix? (1 gallon=128 fl oz). \n" ); document.write( "

Algebra.Com's Answer #668874 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The fraction of oil to total mixture is:
\n" ); document.write( " $\"+1%2F51+\"$
\n" ); document.write( " $\"+%281%2F51%29%2A5%2A128+=+640%2F51+\"$ fl oz of oil
\n" ); document.write( "------------------
\n" ); document.write( " $\"+%28+640%2F51+%2B+x+%29+%2F+%28+640+%2B+x+%29+=+1%2F41+\"$
\n" ); document.write( " $\"+640%2F51+%2B+x+=+%281%2F41%29%2A%28+640+%2B+x+%29+\"$
\n" ); document.write( " $\"+640%2F51+%2B+x+=+640%2F41+%2B+x%2F41+\"$
\n" ); document.write( "Multiply both sides by $\"+41%2A51+\"$
\n" ); document.write( " $\"+41%2A640+%2B+41%2A51%2Ax+=+51%2A640+%2B+51x+\"$
\n" ); document.write( " $\"+40%2A51%2Ax+=+10%2A640+\"$
\n" ); document.write( " $\"++2040x+=+6400+\"$
\n" ); document.write( " $\"+x+=+3.13725+\"$ fl oz of oil shouyld be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+1%2F40+=+%28+12.54902+%2B+3.13725+%29+%2F+%28+640+-+12.54902+-+3.13725+%29+\"$
\n" ); document.write( " $\"+1%2F40+=+15.68627+%2F+624.31373+\"$
\n" ); document.write( " $\"+1%2F40+=+.02512562+\"$
\n" ); document.write( " $\"+1+=+1.00502+\"$
\n" ); document.write( "I expected to be closer
\n" ); document.write( "Check my work
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