document.write( "Question 91885This question is from textbook Beginning Algebra
\n" ); document.write( ": A bus leaves a station at 1pm traveling west at an average speed of 44 mi/h. One hour later another bus leaves the same station traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? \n" ); document.write( "
Algebra.Com's Answer #66883 by ankor@dixie-net.com(22740)\"\" \"About 
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A bus leaves a station at 1 pm traveling west at an average speed of 44 mi/h. One hour later another bus leaves the same station traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
\n" ); document.write( ":
\n" ); document.write( "Let x = traveling time (in hrs) of the 1st bus, when they are 274 mi apart
\n" ); document.write( "Then
\n" ); document.write( "(x-1) = traveling time of the 2nd bus, when they are 274 mi apart
\n" ); document.write( ":
\n" ); document.write( "Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "1st bus dist + 2nd bus dist = 274 mi
\n" ); document.write( "44x + 48(x-1) = 274
\n" ); document.write( "44x + 48x - 48 = 274
\n" ); document.write( "44x + 48x = 274 + 48
\n" ); document.write( "92x = 322
\n" ); document.write( "x = 322/92
\n" ); document.write( "x = 3.5 hrs, which would make it 4:30 PM, when they are 274 mi apart.
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( "44(3.5) + 48(2.5) =
\n" ); document.write( " 154 + 120 = 274 as given
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( "
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