document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053617>Question 1053617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely \r<BR>\n" );
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document.write( "2a^2-5a-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668814 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor completely: 2a^2-5a-3<BR>\n" );
document.write( "1) The coefficient of a^2 is 2 and the constant term is -3. <BR>\n" );
document.write( "2) The product of 2 and -3 is -6. <BR>\n" );
document.write( "3) The factors of -6 which sum to -5 are 1 and -6. <BR>\n" );
document.write( "Let's put it all together:<BR>\n" );
document.write( "2a^2-5a-3 = 2a^2-6a+a-3 = a(2a+1)-3(2a+1)<BR>\n" );
document.write( "Now we can factor 2a+1 and we get:(2a+1)(a-3) </SPAN>\n" );
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