document.write( "Question 1053589: A water trough is 6 m long and its cross-section is an isosceles triangle which is 40 cm wide at the top, and the height is 40 cm. The trough is not full. Give an expression for V, the volume of water in the trough in cm3, when the depth of the water is d cm \n" ); document.write( "
Algebra.Com's Answer #668805 by josmiceli(19441)\"\" \"About 
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The volume would be:
\n" ); document.write( "\"+V+=600%2A%281%2F2%29%2Ab%2Ad+\" cm3
\n" ); document.write( "\"+V+=+300%2Ab%2Ad+\" cm3
\n" ); document.write( "where
\n" ); document.write( "\"+b+\" = base in cm
\n" ); document.write( "\"+d+\" = depth of water in cm
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\n" ); document.write( "The base ( water level in trough ) and depth would
\n" ); document.write( "be proportional to base and depth of trough
\n" ); document.write( "\"+b%2Fd+=+40%2F40+\"
\n" ); document.write( "\"+b+=+d+\"
\n" ); document.write( "--------------------
\n" ); document.write( "\"+V+=+300d%5E2+\" cm3
\n" ); document.write( "Hope I got it\r
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