document.write( "Question 1053505: $7,284
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document.write( "is invested, part at
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document.write( "13%
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document.write( "and the rest at
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document.write( "10%
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document.write( ". If the interest earned from the amount invested at
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document.write( "13%
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document.write( "exceeds the interest earned from the amount invested at
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document.write( "10%
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document.write( "by
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document.write( "$136.86
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document.write( ", how much is invested at each rate? (Round to two decimal places if necessary.) \n" );
document.write( "
Algebra.Com's Answer #668775 by jorel555(1290) ![]() You can put this solution on YOUR website! Let n be the amount invested at 13%. Then: \n" ); document.write( "13n-13686=10(728400-n) \n" ); document.write( "13n-13686=7284000-10n \n" ); document.write( "23n=7297686 \n" ); document.write( "n=317290.7 \n" ); document.write( "Then $3172.91 was invested at 13%, and $ \n" ); document.write( "4111.09 was invested at 10%. ☺☺☺☺ \n" ); document.write( " |