document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053479>Question 1053479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider this scenario: A town has an initial population of 65,000. It grows at a constant rate of 3,500 per year for 4 years. \r<BR>\n" );
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document.write( "When will the output reach 100,000? (The answer may be outside of the reasonable domain.) <BR>\n" );
document.write( "  _________ years after the model began<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668762 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of years. Then:<BR>\n" );
document.write( "100000=65000+3500n<BR>\n" );
document.write( "35000=3500n<BR>\n" );
document.write( "n=10 years before the population reaches 10000. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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