document.write( "Question 1053493: An airplane takes 1 hour longer to go a distance of 375 miles flying against the headwind then on the return trip with a tail wind. if the speed of the wind is 50 miles per hour find the speed of the plane in still air.\r
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Algebra.Com's Answer #668724 by MathTherapy(10549) $\"\"$ $\"About$

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An airplane takes 1 hour longer to go a distance of 375 miles flying against the headwind then on the return trip with a tail wind. if the speed of the wind is 50 miles per hour find the speed of the plane in still air.\r
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Let speed in still air be S
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document.write( "Total speed against the wind: S - 50, and total speed with the wind: S + 50
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document.write( "We then get the following TIME equation: 
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document.write( "375(S + 50) = 375(S - 50) + (S - 50)(S + 50) ------- Multiplying by LCD, (S - 50)(S + 50)
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document.write( "(S - 200)(S + 200) = 0
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document.write( "S, or speed in still air =     OR     S = - 200 (ignore)
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document.write( "It's that simple.
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document.write( "You just need to solve for what is asked for, and that's speed in still air. Solving for time is TOTALLY UNNECESSARY. Don't do it! It makes no sense. \n" );
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