document.write( "Question 1053428: 2 log(x+6) = log36 +log4 what does x= \n" ); document.write( "

Algebra.Com's Answer #668695 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+2%2Alog%28+x+%2B+6+%29+=+log%28+36+%29+%2B+log%28+4+%29+\"$
\n" ); document.write( " $\"+log%28+%28+x+%2B+6+%29%5E2+%29++=+log%28+36%2A4+%29+\"$
\n" ); document.write( " $\"+%28+x+%2B+6+%29%5E2+=+144+\"$
\n" ); document.write( " $\"+x%5E2+%2B+12x+%2B+36+=+144+\"$
\n" ); document.write( "By observation:
\n" ); document.write( " $\"+x%5E2+%2B+12x+%2B+6%5E2+=+12%5E2+\"$
\n" ); document.write( " $\"+%28+x+%2B+6+%29%5E2+=+12%5E2+\"$
\n" ); document.write( " $\"+x+%2B+6+=+12+\"$
\n" ); document.write( " $\"+x+=+6+\"$
\n" ); document.write( "and, also, taking the negative square root of $\"+12%5E2+\"$ ,
\n" ); document.write( " $\"+x+%2B+6+=+-12+\"$
\n" ); document.write( " $\"+x+=+-18+\"$
\n" ); document.write( "This 2nd answer cannot be used because that would
\n" ); document.write( "result in $\"+2%2Alog%28%28+-18+%2B+6+%29%29+=+2%2Alog%28%28+-12+%29%29+\"$ and
\n" ); document.write( "you cannot get a negative result by raising a positive base
\n" ); document.write( "to either a + or a - log
\n" ); document.write( "So the answer is $\"+x+=+6+\"$ \r
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