document.write( "Question 1053360: Find the break-even point for the firm whose cost function C and revenue function R are given. \r
\n" ); document.write( "\n" ); document.write( "C(x)=0.3x+140; R(x)=0.5x \r
\n" ); document.write( "\n" ); document.write( "a. P(680)=340 \r
\n" ); document.write( "\n" ); document.write( "b. P(700)=350 \r
\n" ); document.write( "\n" ); document.write( "c. P(690)=345 \r
\n" ); document.write( "\n" ); document.write( "d. P(720)=360 \r
\n" ); document.write( "\n" ); document.write( "e. P(710)=355 \r
\n" ); document.write( "\n" ); document.write( "Please break this down for me so I can understand. Thank you.
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Algebra.Com's Answer #668598 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
At breakeven, \"C%28x%29=R%28x%29\",
\n" ); document.write( "\"0.3x%2B140=0.5x\"
\n" ); document.write( "\"0.2x=140\"
\n" ); document.write( "\"x=700\"
\n" ); document.write( "The profit function is,
\n" ); document.write( "\"P%28x%29=R%28x%29-C%28x%29\"
\n" ); document.write( "\"P%28x%29=0.5x-%280.3x%2B140%29\"
\n" ); document.write( "\"P%28x%29=0.2x-140\"
\n" ); document.write( "So at \"x=700\"
\n" ); document.write( "\"P%28700%29=0.2%28700%29-140\"
\n" ); document.write( "\"P%28700%29=140-140\"
\n" ); document.write( "\"P%28700%29=0\"
\n" ); document.write( "By definition, at breakeven \"C%28x%29=R%28x%29\" so \"P%28x%29=0\"
\n" ); document.write( "So for \"x%3E700\", you will make profit.
\n" ); document.write( "None of those answers is correct.
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