document.write( "Question 1053304: (3+2i)(3-2i) \n" ); document.write( "

Algebra.Com's Answer #668551 by ikleyn(52856) $\"\"$ $\"About$

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document.write( "Trace attentively each my step:\r\n" );
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document.write( "(3+2i)(3-2i) = 3*3  + 3*(-2i)  + (2i)*3  + (2i)*(-2i) = \r\n" );
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document.write( "                9   - 6i       +  6i     -  =   cancel -6i and 6i;  use  = -1)\r\n" );
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document.write( "                9                        - 4*(-1)      = 9 + 4 = 13.\r\n" );
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document.write( "Or  (3+2i)(3-2i)  =  =  = 9 -4*(-1) = 9 + 4 = 13.\r\n" );
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