document.write( "Question 1053225: Use polynomial division to find the quotient Q(x) and the remainder R(x) when the first polynomial is divided by the second polynomial.\r
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document.write( "1. X^4-x^3+2x^2-x+1, x^2+1\r
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document.write( "2. X^5+32,x-2\r
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document.write( "3. 6x^4-x^2+4, x-3 \n" );
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Algebra.Com's Answer #668505 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x^4-x^3+2x^2-x+1 by x^2+1\r \n" ); document.write( "\n" ); document.write( "=======x^2+x+1 \n" ); document.write( "x^2+1/x^4+x^3+2x^2-x+1 \n" ); document.write( "======x^4+=====x^2 \n" ); document.write( "subtract===x^3+x^2-x+1 \n" ); document.write( "===========x^3+====-x \n" ); document.write( "subtract=======x^2-2x+1 \n" ); document.write( "===============x^2+1 \n" ); document.write( "subtract, and remainder -2x. Q(x)=x^2+x+1, R(x)=-2x \n" ); document.write( "=\r \n" ); document.write( "\n" ); document.write( "x^5+32 by x-2-------------------------------------\r \n" ); document.write( "\n" ); document.write( "=====x^4+2x^3+4x^2+8x+16 \n" ); document.write( "x-2/x^5+0x^4+0x^3+0x^2+0x+32 \n" ); document.write( "====x^5-2x4 \n" ); document.write( "subtract 2x^4+============32 \n" ); document.write( "=========2x^4-4x^3 \n" ); document.write( "subtract======-4x^3========32 \n" ); document.write( "===============4x^3-8x^2 \n" ); document.write( "subtract=============8x^2+32 \n" ); document.write( "=====================8x^2-16x \n" ); document.write( "subtract===================+16x+32 \n" ); document.write( "===========================-16x+32 \n" ); document.write( "subtract====================0 Q(x)=x^4+2x^3+4x^2+8x+16, R(x)=0 \n" ); document.write( "------------------------------------------ \n" ); document.write( "======6x^3+18x^2+53x+159 \n" ); document.write( "x-3/6x^4+0x^3-x^2+0x+4 \n" ); document.write( "====6x^4-18x^3 \n" ); document.write( "subtract 18x^3-x^2+4 \n" ); document.write( "========18x^3-54x^2 \n" ); document.write( "subtract======53x^2+0x+4 \n" ); document.write( "==============53x^2-159x \n" ); document.write( "subtract===========159x+4 \n" ); document.write( "===================159x-477 \n" ); document.write( "subtract================+481 Q(x)=6x^3+18x^2+53x+159. R(x)=481\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |