document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053249>Question 1053249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Peter is one-fifth of his fathers age. Their combined age is 48. Write a linear equation to represent this information. Solve the linear equation. How old is Peter's Father and how old is Peter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668477 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Peter: P<BR>\n" );
document.write( "Father: F<BR>\n" );
document.write( "You can substitute with x and y if required.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "P = 1/5F<BR>\n" );
document.write( "P+F = 48 substitute for P<BR>\n" );
document.write( "1/5F+F = 48<BR>\n" );
document.write( "Multiply both sides times 5:<BR>\n" );
document.write( "F+5F = 240<BR>\n" );
document.write( "6F = 240<BR>\n" );
document.write( "F = 240/6 = 40 The father is 40<BR>\n" );
document.write( "And Peter: 40*1/5 = 40/5 = 8 Peter is 8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );