document.write( "Question 92008: A rancher is planning to put up 220 yards of fencing. In the morning she puts up 80 yards, and in the afternoon she puts up 40% of the remaining fence. What percent of the fence did she put up that day?\r
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Algebra.Com's Answer #66847 by bucky(2189) $\"\"$ $\"About$

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The plan is to put up a total of 220 yards of fencing. In the morning 80 yards are erected,
\n" ); document.write( "so the remaining fence to be installed is 220 yards minus the 80 yards or 140 yards left
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\n" ); document.write( "In the afternoon 40% (or 0.4) of the remaining fence is installed. Since 140 yards is
\n" ); document.write( "the remaining amount and only 0.4 times that is installed, then 140 * 0.4 = 56 yards is
\n" ); document.write( "installed in the afternoon. That means that on that one day a total of 80 + 56 yards or
\n" ); document.write( "136 yards was the amount installed.
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\n" ); document.write( "The percentage of fence installed on that day was 136/220 which is 0.618181 and this converts
\n" ); document.write( "to 61.818% which rounds off to 62%.
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\n" ); document.write( "Hope this helps you to understand the problem. \n" ); document.write( "

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