document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053230>Question 1053230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A delivery driver drove 126 km in 1 hr and 45 min on return journey he held up at some road works so his average speed decreased by 9 km per her how long was he held up at the road work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668462 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 126/1.75=72 kph<BR>\n" );
document.write( "72-9=63<BR>\n" );
document.write( "126/63=2 hours<BR>\n" );
document.write( "2-1.75=.25 hours, or 15 minutes being held up by roadwork. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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